(n+2)^2=(n-4)(n+2)

Solution for (n+2)^2=(n-4)(n+2) equation:

(n+2)^2=(n-4)(n+2)

We move all terms to the left:

(n+2)^2-((n-4)(n+2))=0

We multiply parentheses ..

-((+n^2+2n-4n-8))+(n+2)^2=0


We calculate terms in parentheses: -((+n^2+2n-4n-8)), so:

(+n^2+2n-4n-8)

We get rid of parentheses

n^2+2n-4n-8

We add all the numbers together, and all the variables

n^2-2n-8

Back to the equation:

-(n^2-2n-8)


We get rid of parentheses

-n^2+2n+(n+2)^2+8=0

We add all the numbers together, and all the variables

-1n^2+2n+(n+2)^2+8=0

We move all terms containing n to the left, all other terms to the right

-1n^2+2n+(n+2)^2=-8